
To solve this question, we need to match the complex ions from List I with their correct electronic configurations in List II.
We'll examine each complex ion and determine its electronic configuration based on the oxidation state of the central metal and the coordination chemistry.
Based on the analysis, the correct matching is:
A-II, B-III, C-IV, D-I
Thus, the correct answer is:
A-II, B-III, C-IV, D-I
$[\text{Cr(H}_2\text{O)}_6]^{3+} \text{ contains } \text{Cr}^{3+}: [\text{Ar}]3d^3 \cdot t_{2g}^3 e_g^0$
$[\text{Fe(H}_2\text{O)}_6]^{3+} \text{ contains } \text{Fe}^{3+}: [\text{Ar}]3d^5 \cdot t_{2g}^3 e_g^2$
$[\text{Ni(H}_2\text{O)}_6]^{2+} \text{ contains } \text{Ni}^{2+}: [\text{Ar}]3d^8 \cdot t_{2g}^6 e_g^2$
$[\text{V(H}_2\text{O)}_6]^{3+} \text{ contains } \text{V}^{3+}: [\text{Ar}]3d^2 \cdot t_{2g}^2 e_g^0$

In the first configuration (1) as shown in the figure, four identical charges \( q_0 \) are kept at the corners A, B, C and D of square of side length \( a \). In the second configuration (2), the same charges are shifted to mid points C, E, H, and F of the square. If \( K = \frac{1}{4\pi \epsilon_0} \), the difference between the potential energies of configuration (2) and (1) is given by:
If \( S \) and \( S' \) are the foci of the ellipse \[ \frac{x^2}{18} + \frac{y^2}{9} = 1 \] and \( P \) is a point on the ellipse, then \[ \min (SP \cdot S'P) + \max (SP \cdot S'P) \] is equal to:

Given below are two statements I and II.
Statement I: Dumas method is used for estimation of "Nitrogen" in an organic compound.
Statement II: Dumas method involves the formation of ammonium sulfate by heating the organic compound with concentrated H\(_2\)SO\(_4\). In the light of the above statements, choose the correct answer from the options given below: