\(O - O\) bond length in \(H _2 O _2\) is X than the \(O - O\) bond length in \(F _2 O _2\)The \(O - H\) bond length in \(H _2 O _2\)is Y than that of the\(O - F\) bond in \(F _2 O _2\)Choose the correct option for \(\underline{X} and \underline{Y}\) from those given below :
Electronegativity and atomic size influence bond lengths. Higher electronegativity differences lead to shorter bonds, and smaller atomic radii also contribute to shorter bond lengths.
X-shorter, Y-shorter
X - shorter, Y - longer
X - longer, Y - shorter
X-longer, Y-longer
Step 1: Analyze the O–O bond length
In \(\text{H}_2\text{O}_2\), the oxygen atoms are bonded to hydrogen atoms. In \(\text{F}_2\text{O}_2\), the oxygen atoms are bonded to fluorine atoms. Fluorine is more electronegative than hydrogen. The higher electronegativity of fluorine in \(\text{F}_2\text{O}_2\) leads to a greater pull of electron density towards the fluorine atoms, which weakens the O–O bond and increases its bond length. Therefore, the O–O bond length in \(\text{H}_2\text{O}_2\) is longer than in \(\text{F}_2\text{O}_2\). So, \(X\) is longer.
Step 2: Analyze the O–H and O–F bond lengths
The O–H bond is formed between oxygen and hydrogen, while the O–F bond is formed between oxygen and fluorine. Fluorine has a smaller atomic radius than hydrogen. Also, oxygen and fluorine have much closer electronegativities, leading to a shorter O–F bond compared to the O–H bond where there’s a larger electronegativity difference. Therefore, the O–H bond length in \(\text{H}_2\text{O}_2\) is shorter than the O–F bond length in \(\text{F}_2\text{O}_2\). So, \(Y\) is shorter.
Conclusion
The O–O bond length in \(\text{H}_2\text{O}_2\) is longer than in \(\text{F}_2\text{O}_2\), and the O–H bond length is shorter than the O–F bond length. This corresponds to option (4).
The bond angles \( b_1, b_2, b_3 \) in the above structure are respectively in \( ^\circ \):
The correct order of bond enthalpy \(\left( kJ mol ^{-1}\right)\) is :
Let $\left\lfloor t \right\rfloor$ be the greatest integer less than or equal to $t$. Then the least value of $p \in \mathbb{N}$ for which
\[ \lim_{x \to 0^+} \left( x \left\lfloor \frac{1}{x} \right\rfloor + \left\lfloor \frac{2}{x} \right\rfloor + \dots + \left\lfloor \frac{p}{x} \right\rfloor \right) - x^2 \left( \left\lfloor \frac{1}{x^2} \right\rfloor + \left\lfloor \frac{2}{x^2} \right\rfloor + \dots + \left\lfloor \frac{9^2}{x^2} \right\rfloor \right) \geq 1 \]
is equal to __________.
Such a group of atoms is called a molecule. Obviously, there must be some force that holds these constituent atoms together in the molecules. The attractive force which holds various constituents (atoms, ions, etc.) together in different chemical species is called a chemical bond.
There are 4 types of chemical bonds which are formed by atoms or molecules to yield compounds.