
\(\frac {5}{70}\) moles of pentene will react with \(\frac {5}{70}\) moles of \(Br_2\)
\(= \frac {5}{70} × 160\)
\(= 11.43\ g\)
\(= 1143×10^{-2} g\)
So, the answer is \(1143\).
The reactions which cannot be applied to prepare an alkene by elimination, are
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Match List-I with List-II.
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The expression given below shows the variation of velocity \( v \) with time \( t \): \[ v = \frac{At^2 + Bt}{C + t} \] The dimension of \( A \), \( B \), and \( C \) is:
In organic chemistry, an alkene is a hydrocarbon containing a carbon-carbon double bond.[1]
Alkene is often used as synonym of olefin, that is, any hydrocarbon containing one or more double bonds.
Read More: Ozonolysis
Read More: Unsaturated Hydrocarbon