Question

The product obtained on ozonolysis of 3-Ethylpent-2-ene are

• A. Methanal and 3-Hexanone
• B. Pentalan and Propanone
• C. Ethanal and Pentan-3-one
• D. Ethanal and 3-Hexanone
• E. Ethanal and Butanone

Hint:

During ozonolysis, alkenes are split, and the products are typically carbonyl compounds (aldehydes or ketones) depending on the structure of the original alkene.

Answer 1

The Correct Option is C

Ozonolysis is a reaction in which ozone (O\(_3\)) breaks a carbon-carbon double bond to form ozonides, which then decompose to form carbonyl compounds. In the case of 3-Ethylpent-2-ene, the double bond between the second and third carbon atoms undergoes ozonolysis. This results in the cleavage of the double bond and the formation of two aldehyde or ketone groups. - Option (A): Methanal and 3-Hexanone are not the products of ozonolysis of this compound. - Option (B): Pentalan and Propanone are incorrect and not products of ozonolysis. - Option (C): The correct products of ozonolysis of 3-Ethylpent-2-ene are Ethanal (acetaldehyde) and Pentan-3-one. The cleavage of the double bond results in the formation of these two compounds. - Option (D): Ethanal and 3-Hexanone are not correct, as 3-Hexanone is not the product of ozonolysis in this case. - Option (E): Ethanal and Butanone are incorrect products of this reaction. Thus, the correct answer is (C) Ethanal and Pentan-3-one, which are the products of ozonolysis of 3-Ethylpent-2-ene.