Understanding Hinsberg's Test
Hinsberg's reagent (benzene sulfonyl chloride, \( C_6H_5SO_2Cl \)) is used to distinguish between primary, secondary, and tertiary amines:
Primary amines react to form sulfonamides, which are soluble in alkali.
Secondary amines react to form sulfonamides that are insoluble in alkali.
Tertiary amines do not react with Hinsberg's reagent.
Analyzing the Given Compounds
The compound containing \( \text{NH}_2 \) group (primary amine) reacts with Hinsberg's reagent.
The compound containing a secondary amine (\( -\text{NH}- \) group) also reacts.
Tertiary amines (\( -\text{N}- \)) do not react with Hinsberg's reagent.
Amides and other compounds that do not contain free primary or secondary amine groups will not react.
Counting the Reactive Compounds
After analyzing the given structures, there are \textbf{5 compounds} containing primary or secondary amines that will react with Hinsberg's reagent.
Conclusion
The number of compounds that give a reaction with Hinsberg's reagent is 5.
The descending order of basicity of following amines is :
Choose the correct answer from the options given below :
Which of the following amine(s) show(s) positive carbamylamine test?
The correct order of basicity for the following molecules is:
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: