Match the LIST-I with LIST-II
LIST-I | LIST-II |
---|---|
A. PF5 | I. dsp2 |
B. SF6 | II. sp3d |
C. Ni(CO)4 | III. sp3d2 |
D. [PtCl4]2- | IV. sp3 |
Choose the correct answer from the options given below:
PF5:
5σ + 0 lone pair ⇒ sp3d hybridisation
SF6:
6σ + 0 lone pair ⇒ sp3d2 hybridisation
Ni(CO)4:
Ni oxidation state = 0
In presence of ligand field:
Ni(0): [Ar] ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ _ _ _ _
Orbitals: 3d, 4s, 4p
⇒ sp3 hybridisation
[PtCl4]2-:
Pt oxidation state = +2
In presence of ligand field:
Pt2+: [Kr] ↑↓ ↑↓ ↑↓ ↑↓ _ _ _
Orbitals: 5d, 6s, 6p
⇒ dsp2 hybridisation
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: