Question:

Match the LIST-I with LIST-II

LIST-ILIST-II
A. PF5I. dsp2
B. SF6II. sp3d
C. Ni(CO)4III. sp3d2
D. [PtCl4]2-IV. sp3

Choose the correct answer from the options given below:

Show Hint

Determine the hybridization of the central atom in each molecule/ion by counting the number of sigma bonds and lone pairs.
Updated On: Apr 24, 2025
  • A-II, B-III, C-IV, D-I
  • A-IV, B-I, C-II, D-III
  • A-I, B-II, C-III, D-IV
  • A-III, B-I, C-IV, D-II
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

PF5:
5σ + 0 lone pair ⇒ sp3d hybridisation

SF6:
6σ + 0 lone pair ⇒ sp3d2 hybridisation

Ni(CO)4:
Ni oxidation state = 0
In presence of ligand field:
Ni(0): [Ar] ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ _ _ _ _
Orbitals: 3d, 4s, 4p
⇒ sp3 hybridisation

[PtCl4]2-:
Pt oxidation state = +2
In presence of ligand field:
Pt2+: [Kr] ↑↓ ↑↓ ↑↓ ↑↓ _ _ _
Orbitals: 5d, 6s, 6p
⇒ dsp2 hybridisation

Was this answer helpful?
0
0