Question

Match the List I with List II
1- Bromopropane is reacted with regents in List I to give products in List II

	List I-Reagent		List II-Product
(A)	KOH(alc)	I	Nitrile
(B)	KCL(alc)	II	Ester
(C)	AgNo2	III	Alkene
(D)	H3CC00Ag	III	Nitroalkane

Choose the correct answer from the options given below:

• A. A-IV, B-III, C-II, D-I
• B. A-III, B-I, C-IV, D-II
• C. A-I, B-III, C-IV, D-II
• D. A-I, B-II, C-III, D-IV

Answer 1

The Correct Option is B

The reactions of bromopropane with the given reagents are as follows: 1. A. Reaction with KOH (alc): Bromopropane reacts with alcoholic KOH to undergo dehydrohalogenation, forming an alkene. \[ \text{CH}_3-\text{CH}_2-\text{CH}_2\text{Br} + \text{KOH(alc)} \rightarrow \text{CH}_3-\text{CH}=\text{CH}_2 \, (\text{Alkene}). \] 2. B. Reaction with KCN (alc): Bromopropane reacts with alcoholic KCN to undergo a nucleophilic substitution reaction, forming a nitrile. \[ \text{CH}_3-\text{CH}_2-\text{CH}_2\text{Br} + \text{KCN} \rightarrow \text{CH}_3-\text{CH}_2-\text{CH}_2\text{CN} \, (\text{Nitrile}). \] 3. C. Reaction with AgNO\(_2\): Bromopropane reacts with silver nitrite (AgNO\(_2\)) to form a nitroalkane via substitution. \[ \text{CH}_3-\text{CH}_2-\text{CH}_2\text{Br} + \text{AgNO}_2 \rightarrow \text{CH}_3-\text{CH}_2-\text{CH}_2\text{NO}_2 + \text{AgBr} \, (\text{Nitroalkane}). \] 4. D. Reaction with H\(_3\)CCOOAg: Bromopropane reacts with silver acetate (H\(_3\)CCOOAg) to form an ester via substitution. \[ \text{CH}_3-\text{CH}_2-\text{CH}_2\text{Br} + \text{CH}_3\text{COOAg} \rightarrow \text{CH}_3-\text{CH}_2-\text{CH}_2\text{COOCH}_3 + \text{AgBr} \, (\text{Ester}). \] Thus, the correct matching is: \[ \text{A–III, B–I, C–IV, D–II}. \]