Question:
Match List I with List IILIST I LIST II A Cobalt catalyst I \((H_2+Cl_2)\) production B Syngas II Water gas production C Nickel catalyst III Coal gasification D Brine solution IV Methanol production
Choose the correct answer from the options given below:
Match List I with List II
Choose the correct answer from the options given below:
| LIST I | LIST II | ||
| A | Cobalt catalyst | I | \((H_2+Cl_2)\) production |
| B | Syngas | II | Water gas production |
| C | Nickel catalyst | III | Coal gasification |
| D | Brine solution | IV | Methanol production |
Updated On: Jul 6, 2024
- A-IV, B-III, C-I, D-II
- A-II, B-III, C-IV, D-I
- A-IV, B-I, C-II, D-III
- A-IV, B-III, C-II, D-I
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
(A) Cobalt catalyst Methanol production
(B) Syn gas Coal gasification
(C) Nickel catalyst Water gas production
(D) Brine solution Production
aq.
(B) Syn gas Coal gasification
(C) Nickel catalyst Water gas production
(D) Brine solution Production
aq.
Therefore, The correct answer is option (D): A-IV, B-III, C-II, D-I
Was this answer helpful?
1
3
Top Questions on Types of Solutions
- Fehling’s solution ‘A’ is
- NEET (UG) - 2024
- Chemistry
- Types of Solutions
- Which among the following purification methods is based on the principle of “Solubility” in two different solvents?
- JEE Main - 2024
- Chemistry
- Types of Solutions
- Match List I with List IIChoose the correct answer from the options given below:
LIST I LIST II A Cobalt catalyst 1 (H2+Cl2) production B Syngas 2 Water gas production C Nickel catalyst 3 Coal gasification D Brine solution 4 Methanol production - JEE Main - 2023
- Chemistry
- Types of Solutions
A solution of Fe2(SO4)3 is electrolyzed for ‘x’ min with a current of 1.5 A to deposit 0.3482 g of Fe. The value of x is _______. [nearest integer]
Given : 1 F = 96500 C mol–1.
Atomic mass of Fe = 56 g mol–1
- JEE Main - 2022
- Chemistry
- Types of Solutions
- The mixture which shows positive deviation from Raoult’s law i s :
- NEET (UG) - 2020
- Chemistry
- Types of Solutions
View More Questions
Questions Asked in JEE Main exam
- Let \[ \vec{a} = 2\hat{i} + \alpha \hat{j} + \hat{k}, \quad \vec{b} = -\hat{i} + \hat{k}, \quad \vec{c} = \beta \hat{j} - \hat{k}, \] where \( \alpha \) and \( \beta \) are integers and \( \alpha \beta = -6 \). Let the values of the ordered pair \( (\alpha, \beta) \) for which the area of the parallelogram of diagonals \( \vec{a} + \vec{b} \) and \( \vec{b} + \vec{c} \) is \( \frac{\sqrt{21}}{2} \), be \( (\alpha_1, \beta_1) \) and \( (\alpha_2, \beta_2) \). Then \( \alpha_1^2 + \beta_1^2 - \alpha_2 \beta_2 \) is equal to:
- JEE Main - 2024
- Vectors
- The molecular formula of second homologue in the homologous series of monocarboxylic acid is
- JEE Main - 2024
- Aldehydes, Ketones and Carboxylic Acids
- Given below are two statements: Statement I: $\text{PF}_5$ and $\text{BrF}_5$ both exhibit $\text{sp}^3\text{d}$ hybridisation.Statement II: Both $\text{SF}_6$ and $[\text{Co}(\text{NH}_3)_6]^{3+}$ exhibit $\text{sp}^3\text{d}^2$ hybridisation. In the light of the above statements,choose the correct answer from the options given below:
- JEE Main - 2024
- Hybridisation
- Consider the system of linear equations \( x + y + z = 4\mu \), \( x + 2y + 2\lambda z = 10\mu \), \( x + 3y + 4\lambda^2 z = \mu^2 + 15 \), where \( \lambda, \mu \in \mathbb{R} \). Which one of the following statements is NOT correct?
- JEE Main - 2024
- Linear Algebra
- If the constant term in the expansion of \((1 + 2x - 3x^3) \left(\frac{3}{2}x^2 - \frac{1}{3x}\right)^9\) is \( p \), then \( 108p \) is equal to _________.
- JEE Main - 2024
- Algebra
View More Questions
Concepts Used:
Solutions
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
Types of Solutions:
The solutions can be classified into three types:
- Solid Solutions - In these solutions, the solvent is in a Solid-state.
- Liquid Solutions- In these solutions, the solvent is in a Liquid state.
- Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:
- Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
- Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
- Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.