Question

Match List I with List II

List-I (Element)	List-II (Electronic Configuration)
A. N	I. [Ar] 3d10 4s2 4p5
B. S	II. [Ne] 3s2 3p4
C. Br	III. [He] 2s2 2p3
D. Kr	IV. [Ar] 3d10 4s2 4p6

Choose the correct answer from the options given below:

• A. A-IV, B-III, C-II, D-I
• B. A-III, B-II, C-I, D-IV
• C. A-I, B-IV, C-III, D-II
• D. A-II, B-I, C-IV, D-III

Answer 1

The Correct Option is B

The question requires matching elements with their respective electronic configurations. Let's analyze each element's correct electronic configuration to identify the correct match.

1. Nitrogen (N): The atomic number of nitrogen is 7. The electronic configuration of nitrogen is \([He] 2s^2 2p^3\). Therefore, it corresponds to the option III.
2. Sulfur (S): The atomic number of sulfur is 16. The electronic configuration of sulfur is \([Ne] 3s^2 3p^4\). Hence, it corresponds to the option II.
3. Bromine (Br): The atomic number of bromine is 35. The electronic configuration of bromine is \([Ar] 3d^{10} 4s^2 4p^5\). Thus, it corresponds to the option I.
4. Krypton (Kr): The atomic number of krypton is 36. The electronic configuration of krypton is \([Ar] 3d^{10} 4s^2 4p^6\). Therefore, it matches with the option IV.

From the analysis above, the correct matching is:

List-I (Element)	List-II (Electronic Configuration)
A. N	III. [He] 2s2 2p3
B. S	II. [Ne] 3s2 3p4
C. Br	I. [Ar] 3d10 4s2 4p5
D. Kr	IV. [Ar] 3d10 4s2 4p6

Thus, the correct answer is: A-III, B-II, C-I, D-IV.

Answer 2

Let us match the electronic configurations: 
A. N (Nitrogen):} Nitrogen has the electronic configuration $1s^2 2s^2 2p^3$, which corresponds to configuration III. 
B. S (Sulfur):} Sulfur has the electronic configuration $[\text{Ne}] 3s^2 3p^4$, which corresponds to configuration II.
C. Br (Bromine):} Bromine has the electronic configuration $[\text{Ar}] 3d^{10} 4s^2 4p^5$, which corresponds to configuration I.
D. Kr (Krypton):} Krypton has the electronic configuration $[\text{Ar}] 3d^{10} 4s^2 4p^6$, which corresponds to configuration IV.
Thus, the correct match is A-III, B-II, C-I, D-IV. Hence, the answer is (2).