Question:
Match List I with List II:List I
List II
A 16 g of CH4 (g) I Weight 28g B 1 g of H2 (g) II 60.2 × 1023 electrons C 1 mole of N2 (g) III Weighs 32 g D 0.5 mol of SO2 (g) IV Occupies 11.4 L volume at STP
Choose the correct answer from the options given below:
Match List I with List II:
Choose the correct answer from the options given below:
List I | List II | ||
| A | 16 g of CH4 (g) | I | Weight 28g |
| B | 1 g of H2 (g) | II | 60.2 × 1023 electrons |
| C | 1 mole of N2 (g) | III | Weighs 32 g |
| D | 0.5 mol of SO2 (g) | IV | Occupies 11.4 L volume at STP |
Updated On: Mar 21, 2025
- A-II, B-IV, C-III, D-I
- A-I, B-III, C-II, D-IV
- A-II, B-IV, C-I, D-III
- A-II, B-III, C-IV, D-I
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The Correct Option is C
Solution and Explanation
16g CH4 = 1 mole CH4 contains 10 × 6.02 × 1023 electrons
= 60.2 × 1023
1g H2 = 0.5 mole H2 gas occupy 11.35 litre volume at STP
1 mole of N2 = 28g
0.5 mole of SO2 = 32g
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