Step 1: Recall Graham's law of diffusion, which states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass: \[ \text{Rate} \propto \frac{1}{\sqrt{M}}, \] where \( M \) is the molar mass of the gas.
Step 2: Compare the molar masses of the given gases:
- O\(_2\): \( 32 \, \text{g/mol} \),
- CO\(_2\): \( 44 \, \text{g/mol} \),
- H\(_2\): \( 2 \, \text{g/mol} \),
- N\(_2\): \( 28 \, \text{g/mol} \).
Step 3: Determine the gas with the lowest molar mass.
H\(_2\) has the smallest molar mass (2 g/mol), so it will have the highest rate of diffusion.