Question:

Match List-I with List-II.
List-I
Alkali Metal
List-II
Emission Wavelength
in nm
(A) Li(I) 589.2
(B) Na(II) 455.5
(C) Rb(III) 670.8
(D) Cs(IV) 780.0
Choose the correct answer from the options given below:

Updated On: Nov 3, 2025
  • (A)-(I), (B)-(IV), (C)-(III), (D)-(II)
  • (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  • (A)-(IV), (B)-(II), (C)-(I), (D)-(III)
  • (A)-(II), (B)-(IV), (C)-(III), (D)-(I)
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The Correct Option is B

Approach Solution - 1

To solve this problem, we need to match the alkali metals in List-I with their corresponding emission wavelengths given in List-II. Alkali metals are known for their characteristic colors when excited, and these colors correspond to specific wavelengths of light emitted during transitions. Let's explore each metal's emission wavelength:

  1. Lithium (Li) is known to emit a red color when it is excited, with a characteristic emission wavelength of approximately 670.8 nm. This corresponds to option (III).
  2. Sodium (Na) produces a bright yellow flame, which corresponds to 589.2 nm. This is option (I).
  3. Rubidium (Rb) exhibits a reddish-violet flame with an emission wavelength of approximately 780.0 nm. This matches option (IV).
  4. Cesium (Cs) shows a violet-blue flame, associated with an emission wavelength of 455.5 nm. This is option (II).

From the above analysis, we can match the metals with their corresponding wavelengths as follows:

  • (A) Li - (III) 670.8 nm
  • (B) Na - (I) 589.2 nm
  • (C) Rb - (IV) 780.0 nm
  • (D) Cs - (II) 455.5 nm

Therefore, the correct answer is: (A)-(III), (B)-(I), (C)-(IV), (D)-(II).

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Approach Solution -2

This is a fact-based question regarding the emission wavelengths of alkali metals. The correct matches based on known data are:

(A) Li – (III) 670.8 nm
(B) Na – (I) 589.2 nm
(C) Rb – (IV) 780.0 nm
(D) Cs – (II) 455.5 nm

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