| List-I Alkali Metal | List-II Emission Wavelength in nm |
|---|---|
| (A) Li | (I) 589.2 |
| (B) Na | (II) 455.5 |
| (C) Rb | (III) 670.8 |
| (D) Cs | (IV) 780.0 |
To solve this problem, we need to match the alkali metals in List-I with their corresponding emission wavelengths given in List-II. Alkali metals are known for their characteristic colors when excited, and these colors correspond to specific wavelengths of light emitted during transitions. Let's explore each metal's emission wavelength:
From the above analysis, we can match the metals with their corresponding wavelengths as follows:
Therefore, the correct answer is: (A)-(III), (B)-(I), (C)-(IV), (D)-(II).
This is a fact-based question regarding the emission wavelengths of alkali metals. The correct matches based on known data are:
(A) Li – (III) 670.8 nm
(B) Na – (I) 589.2 nm
(C) Rb – (IV) 780.0 nm
(D) Cs – (II) 455.5 nm
Let \( C_{t-1} = 28, C_t = 56 \) and \( C_{t+1} = 70 \). Let \( A(4 \cos t, 4 \sin t), B(2 \sin t, -2 \cos t) \text{ and } C(3r - n_1, r^2 - n - 1) \) be the vertices of a triangle ABC, where \( t \) is a parameter. If \( (3x - 1)^2 + (3y)^2 = \alpha \) is the locus of the centroid of triangle ABC, then \( \alpha \) equals: