| List-I Alkali Metal | List-II Emission Wavelength in nm |
|---|---|
| (A) Li | (I) 589.2 |
| (B) Na | (II) 455.5 |
| (C) Rb | (III) 670.8 |
| (D) Cs | (IV) 780.0 |
To solve this problem, we need to match the alkali metals in List-I with their corresponding emission wavelengths given in List-II. Alkali metals are known for their characteristic colors when excited, and these colors correspond to specific wavelengths of light emitted during transitions. Let's explore each metal's emission wavelength:
From the above analysis, we can match the metals with their corresponding wavelengths as follows:
Therefore, the correct answer is: (A)-(III), (B)-(I), (C)-(IV), (D)-(II).
This is a fact-based question regarding the emission wavelengths of alkali metals. The correct matches based on known data are:
(A) Li – (III) 670.8 nm
(B) Na – (I) 589.2 nm
(C) Rb – (IV) 780.0 nm
(D) Cs – (II) 455.5 nm
Match List - I with List - II:
List - I:
(A) Electric field inside (distance \( r > 0 \) from center) of a uniformly charged spherical shell with surface charge density \( \sigma \), and radius \( R \).
(B) Electric field at distance \( r > 0 \) from a uniformly charged infinite plane sheet with surface charge density \( \sigma \).
(C) Electric field outside (distance \( r > 0 \) from center) of a uniformly charged spherical shell with surface charge density \( \sigma \), and radius \( R \).
(D) Electric field between two oppositely charged infinite plane parallel sheets with uniform surface charge density \( \sigma \).
List - II:
(I) \( \frac{\sigma}{\epsilon_0} \)
(II) \( \frac{\sigma}{2\epsilon_0} \)
(III) 0
(IV) \( \frac{\sigma}{\epsilon_0 r^2} \) Choose the correct answer from the options given below: