Question

Match List I with List II

List I (Complex)		List II (Hybridization)
A.	Ni(CO)4	I.	sp3
B.	[Cu(NH3)4]2+	II.	dsp2
C.	[Fe(NH3)6]2+	III.	sp3d2
D.	[Fe(H2O)6]2+	IV.	d2sp3

Choose the correct answer from the options given below:

• A. A-I, B-II, C-III, D-IV
• B. A-II, B-I, C-III, D-IV
• C. A-I, B-II, C-IV, D-III
• D. A-II, B-I, C-IV, D-III

Answer 1

The Correct Option is C

For \([Fe(NH_3)_6]^{2+}\), \(\Delta_0 < P\), hence the pairing of electrons does not occur in \(t_{2g}\). Therefore, the complex is outer orbital and its hybridisation is \(sp^3d^2\).
(A) \([Ni(CO)_4]\) - \(sp^3\) 
(B) \([Cu(NH_3)_4]^{2+}\) - \(dsp^2\) 
(C) \([Fe(NH_3)_6]^{2+}\) - \(sp^3d^2\) 
(D) \([Fe(H_2O)_6]^{2+}\) - \(sp^3d^2\) 
Thus, the correct match is: \[ \text{A - I, B - II, C - IV, D - III.} \]