Match List I with List IIList I (Complex) List II (Hybridization) A. Ni(CO)4 I. sp3 B. [Cu(NH3)4]2+ II. dsp2 C. [Fe(NH3)6]2+ III. sp3d2 D. [Fe(H2O)6]2+ IV. d2sp3
Choose the correct answer from the options given below:
| List I (Complex) | List II (Hybridization) | ||
| A. | Ni(CO)4 | I. | sp3 |
| B. | [Cu(NH3)4]2+ | II. | dsp2 |
| C. | [Fe(NH3)6]2+ | III. | sp3d2 |
| D. | [Fe(H2O)6]2+ | IV. | d2sp3 |
- A-I, B-II, C-III, D-IV
- A-II, B-I, C-III, D-IV
- A-I, B-II, C-IV, D-III
- A-II, B-I, C-IV, D-III
The Correct Option is C
Solution and Explanation
For \([Fe(NH_3)_6]^{2+}\), \(\Delta_0 < P\), hence the pairing of electrons does not occur in \(t_{2g}\). Therefore, the complex is outer orbital and its hybridisation is \(sp^3d^2\).
(A) \([Ni(CO)_4]\) - \(sp^3\)
(B) \([Cu(NH_3)_4]^{2+}\) - \(dsp^2\)
(C) \([Fe(NH_3)_6]^{2+}\) - \(sp^3d^2\)
(D) \([Fe(H_2O)_6]^{2+}\) - \(sp^3d^2\)
Thus, the correct match is: \[ \text{A - I, B - II, C - IV, D - III.} \]
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A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
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