Question

Match List I with List II

Choose the correct answer from the options given below:

• A. A-III, B-IV, C-II, D-I
• B. A-III, B-IV, C-I, D-II
• C. A-IV, B-III, C-I, D-II
• D. A-IV, B-III, C-II, D-I

Answer 1

The Correct Option is C

Based on biomolecules theory and the structure of the named compounds:
\(\alpha\)-Glucose and \(\alpha\)-Galactose are epimers, differing in configuration around one specific carbon atom.
\(\alpha\)-Glucose and \(\beta\)-Glucose are anomers, differing at the anomeric carbon.
\(\alpha\)-Glucose and \(\alpha\)-Fructose are functional isomers, as they have different functional groups.
\(\alpha\)-Glucose and \(\alpha\)-Ribose are from different homologous series.

Answer 2

Step 1: Understand the question
We are asked to match pairs of compounds from List I with their correct relationship types from List II. The relationships include anomers, epimers, functional isomers, and homologous. Each pair of compounds must be analyzed based on structural and functional differences.

Step 2: Analyze each pair
(A) α-Glucose and α-Galactose
These two differ only in the configuration at carbon atom C-4 of the glucose chain. Such compounds are called epimers (isomers differing at one carbon atom other than the anomeric carbon).
Hence, A → IV (Epimers).

(B) α-Glucose and β-Glucose
These two differ only in the configuration around the anomeric carbon (C-1). When two cyclic forms of the same sugar differ only at the anomeric carbon, they are called anomers.
Hence, B → III (Anomers).

(C) α-Glucose and α-Fructose
These two have the same molecular formula (C₆H₁₂O₆) but differ in the functional group: glucose is an aldose (contains an aldehyde group) and fructose is a ketose (contains a ketone group). Therefore, they are functional isomers.
Hence, C → I (Functional isomers).

(D) α-Glucose and α-Ribose
Glucose (C₆H₁₂O₆) and ribose (C₅H₁₀O₅) differ by one CH₂O unit. Such compounds are said to be homologous because they belong to the same homologous series, differing by one –CH₂– group.
Hence, D → II (Homologous).

Step 3: Final matching
A → IV (Epimers)
B → III (Anomers)
C → I (Functional isomers)
D → II (Homologous)

Final answer

A-IV, B-III, C-I, D-II