List I (Anion) | List II (gas evolved on reaction with dil \(H_2SO_4\)) | ||
---|---|---|---|
A. | \(CO_3^{ 2−}\) | I. | Colourless gas which turns lead acetate paper black. |
B. | \(S^{2–}\) | II. | Colourless gas which turns acidified potassium dichromate solution green |
C. | \(SO_3^{ 2−}\) | III. | Brown fumes which turns acidified KI solution containing starch blue. |
D. | \(NO_2^{−}\) | IV. | Colourless gas evolved with brisk effervescence, which turns lime water milky. |
\(CO_3^{ 2−}\): On action of diluted sulphuric acid, \(CO_2\) gas is released which turns lime water milky.
\(S ^{2-}:\) On action of diluted sulphuric acid, \(H_2S\) gas is released which turns lead acetate paper black.
\(SO_3^{ 2−}\): On action of diluted \( H_2SO_4, SO_2\) gas is evolved which turns acidified potassium dichromate solution green.
\(NO^{2−}\): On action of dil \(H_2SO_4, NO_2\) gas is evolved which turns Kl solution contain starch blue.
\(Hence,\) the correct option is (D): \(A-IV, B-I, C-II, D-III\)
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
Find the IUPAC name of the compound.
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32
The gas laws were developed at the end of the 18th century, when scientists began to realize that relationships between pressure, volume and temperature of a sample of gas could be obtained which would hold to approximation for all gases.