Question:
Match List I with List II. List I (Anion) List II (gas evolved on reaction with dil \(H_2SO_4\)) A. \(CO_3^{ 2−}\) I. Colourless gas which turns lead acetate paper black. B. \(S^{2–}\) II. Colourless gas which turns acidified potassium dichromate solution green C. \(SO_3^{ 2−}\) III. Brown fumes which turns acidified KI solution containing starch blue. D. \(NO_2^{−}\) IV. Colourless gas evolved with brisk effervescence, which turns lime water milky.
Choose the correct answer from the options given below:
Match List I with List II.
Choose the correct answer from the options given below:
| List I (Anion) | List II (gas evolved on reaction with dil \(H_2SO_4\)) | ||
|---|---|---|---|
| A. | \(CO_3^{ 2−}\) | I. | Colourless gas which turns lead acetate paper black. |
| B. | \(S^{2–}\) | II. | Colourless gas which turns acidified potassium dichromate solution green |
| C. | \(SO_3^{ 2−}\) | III. | Brown fumes which turns acidified KI solution containing starch blue. |
| D. | \(NO_2^{−}\) | IV. | Colourless gas evolved with brisk effervescence, which turns lime water milky. |
Updated On: Jul 6, 2024
- A-III, B-I, C-II, D-IV
- A-II, B-I, C-IV, D-III
- A-IV, B-I, C-III, D-II
- A-IV, B-I, C-II, D-III
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The Correct Option is D
Solution and Explanation
\(CO_3^{ 2−}\): On action of diluted sulphuric acid, \(CO_2\) gas is released which turns lime water milky.
\(S ^{2-}:\) On action of diluted sulphuric acid, \(H_2S\) gas is released which turns lead acetate paper black.
\(SO_3^{ 2−}\): On action of diluted \( H_2SO_4, SO_2\) gas is evolved which turns acidified potassium dichromate solution green.
\(NO^{2−}\): On action of dil \(H_2SO_4, NO_2\) gas is evolved which turns Kl solution contain starch blue.
\(Hence,\) the correct option is (D): \(A-IV, B-I, C-II, D-III\)
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