Question:

Let z1, z2 and z3 be three distinct points in the complex plane such that the segment joining z1 and z2 is perpendicular to the segment joining z1 and z2. If |z1-z2|=5 and|z1-z3|=12 then|z2-z3| is equal to

Updated On: Apr 4, 2025
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The Correct Option is C

Solution and Explanation

We are given three distinct points \(z_1, z_2, z_3\) in the complex plane such that:

  • The segment joining \(z_1\) and \(z_2\) is perpendicular to the segment joining \(z_1\) and \(z_3\).
  • \(|z_1 - z_2| = 5\) and \(|z_1 - z_3| = 12\).

We need to find \(|z_2 - z_3|\)

Since the segment joining \(z_1\) and \(z_2\) is perpendicular to the segment joining \(z_1\) and \(z_3\), we can apply the Pythagorean theorem in the right triangle formed by the points \(z_1 \), \( z_2 \), \( z_3\).

According to the Pythagorean theorem:

\(|z_2 - z_3|^2 = |z_1 - z_2|^2 + |z_1 - z_3|^2\)

Substituting the given values:

\(|z_2 - z_3|^2 = 5^2 + 12^2 = 25 + 144 = 169\)

\(|z_2 - z_3| = \sqrt{169} = 13\)

The answer is 13.

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