Question:

Let \( X \) be a standard normal random variable. Then \( P(X^3 - 2X^2 - X + 2 > 0) \) equals

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When solving inequalities involving standard normal variables, it's often helpful to express the inequality in terms of the cumulative distribution function \( \Phi \).
Updated On: Dec 17, 2025
  • \( 2\Phi(1) - 1 \)
  • \( 1 - \Phi(2) \)
  • \( 2\Phi(1) - \Phi(2) \)
  • \( \Phi(2) - \Phi(1) \)
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The Correct Option is C

Solution and Explanation

Step 1: Rewrite the expression. 
The given inequality \( X^3 - 2X^2 - X + 2 > 0 \) involves a cubic function of \( X \), which we solve numerically or use standard normal distribution tables to evaluate.

Step 2: Numerical approximation. 
By analyzing the roots of the cubic function and using the properties of the standard normal distribution, we find that: \[ P(X^3 - 2X^2 - X + 2 > 0) = 2\Phi(1) - \Phi(2). \]

Step 3: Conclusion. 
The correct answer is (C) \( 2\Phi(1) - \Phi(2) \).

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