Question:
Let π and π be jointly distributed random variables such that, for every fixed π>0, the conditional distribution of π given π=π is the Poisson distribution with mean π. If the distribution of π is πΊππππ (2, \(\frac{1}{2}\) ), then the value of π(π= 0)+π(π=1) equals
Let π and π be jointly distributed random variables such that, for every fixed π>0, the conditional distribution of π given π=π is the Poisson distribution with mean π. If the distribution of π is πΊππππ (2, \(\frac{1}{2}\) ), then the value of π(π= 0)+π(π=1) equals
Updated On: Oct 1, 2024
- \(\frac{7}{27}\)
- \(\frac{20}{27}\)
- \(\frac{8}{27}\)
- \(\frac{16}{27}\)
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The Correct Option is B
Solution and Explanation
The correct option is (B): \(\frac{20}{27}\)
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