The correct answer is (A) : 21 a11
Let first term of G.P. be a and common ratio is r
Then, \(\frac{α}{1-r} = 5....(i)\)
\(α =\frac{(r^5-1)}{(r-1)}\)
\(= \frac{98}{25}\)
\(⇒ 1-r^5 = \frac{98}{125}\)
\(∴ r^5 = \frac{27}{125}\)
\(r = (\frac{3}{5})^{\frac{3}{5}}\)
∴ Then, \(S_{21} = \frac{21}{2}[2×10ar + 20×10ar^2]\)
\(= 21[10ar+10.10ar^2]\)
\(= ^{21}α_{11}\)
A geometric progression is the sequence, in which each term is varied by another by a common ratio. The next term of the sequence is produced when we multiply a constant to the previous term. It is represented by: a, ar1, ar2, ar3, ar4, and so on.
Important properties of GP are as follows:
If a1, a2, a3,… is a GP of positive terms then log a1, log a2, log a3,… is an AP (arithmetic progression) and vice versa