Question:

Let the sum of an infinite G.P., whose first term is a and the common ratio is r, be 5. Let the sum of its first five terms be 98/25. Then the sum of the first 21 terms of an AP, whose first term is 10ar, nth term is an and the common difference is 10ar2, is equal to

Updated On: Jun 29, 2025
  • 21 a11
  • 22 a11
  • 15 a16
  • 14 a16
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

The correct answer is (A) : 21 a11
Let first term of G.P. be a and common ratio is r
Then, \(\frac{α}{1-r} = 5....(i)\)
\(α =\frac{(r^5-1)}{(r-1)}\)
\(= \frac{98}{25}\)
\(⇒ 1-r^5 = \frac{98}{125}\)
\(∴ r^5 = \frac{27}{125}\)
\(r = (\frac{3}{5})^{\frac{3}{5}}\)
∴ Then, \(S_{21} = \frac{21}{2}[2×10ar + 20×10ar^2]\)
\(= 21[10ar+10.10ar^2]\)
\(= ^{21}α_{11}\)

Was this answer helpful?
3
1

Concepts Used:

Geometric Progression

What is Geometric Sequence?

A geometric progression is the sequence, in which each term is varied by another by a common ratio. The next term of the sequence is produced when we multiply a constant to the previous term. It is represented by: a, ar1, ar2, ar3, ar4, and so on.

Properties of Geometric Progression (GP)

Important properties of GP are as follows:

  • Three non-zero terms a, b, c are in GP if  b2 = ac
  • In a GP,
    Three consecutive terms are as a/r, a, ar
    Four consecutive terms are as a/r3, a/r, ar, ar3
  • In a finite GP, the product of the terms equidistant from the beginning and the end term is the same that means, t1.tn = t2.tn-1 = t3.tn-2 = …..
  • If each term of a GP is multiplied or divided by a non-zero constant, then the resulting sequence is also a GP with a common ratio
  • The product and quotient of two GP’s is again a GP
  • If each term of a GP is raised to power by the same non-zero quantity, the resultant sequence is also a GP.

If a1, a2, a3,… is a GP of positive terms then log a1, log a2, log a3,… is an AP (arithmetic progression) and vice versa