Given that \( a, a r, a r^2 \) are in a geometric progression (G.P.), we know the property of a G.P. is that the ratio between consecutive terms is constant. Therefore:
\[
\frac{a r}{a} = \frac{a r^2}{a r}
\]
Simplifying both sides:
\[
r = r
\]
This confirms that the sequence is indeed in G.P. Now, we need to evaluate the given expression:
\[
\left| a \quad a r \right| \quad \left| a r^2 \quad a r^3 \right| = \left| a r^3 \quad a r^6 \right|
\]
By multiplying the determinants:
\[
\left| a \quad a r \right| = a^2 r, \quad \left| a r^2 \quad a r^3 \right| = a^2 r^5, \quad \left| a r^3 \quad a r^6 \right| = a^2 r^9
\]
Thus, the equation becomes:
\[
a^2 r \cdot a^2 r^5 = a^2 r^9
\]
This simplifies to:
\[
a^4 r^6 = a^2 r^9
\]
Finally, dividing both sides by \( a^2 r^6 \):
\[
a^2 r^4 = a^2 r^4
\]
Thus, the correct value is \( r^4 \), which corresponds to option (B).