Question:

Let \( S = \{ z \in \mathbb{C} : |z - 1 + i| = 1 \} \) represents:

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The equation \( |z - (a + bi)| = r \) represents a circle with center at \( (a, b) \) and radius \( r \).
Updated On: May 15, 2025
  • a circle with centre \( (-1, 1) \) and radius 1 unit
  • a circle with centre \( (1, 2) \) and radius 5 units
  • a circle with centre \( (-1, -1) \) and radius 1 unit
  • an ellipse with centre \( (-1, -1) \)
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The Correct Option is C

Solution and Explanation

We are given the equation \( |z - (1 - i)| = 1 \), which describes a geometric figure in the complex plane. The general form for a circle in the complex plane is \( |z - c| = r \), where \( c \) is the center of the circle and \( r \) is the radius. Here, the equation is: \[ |z - (1 - i)| = 1 \] This represents a circle with center \( (1, -1) \) (as \( 1 - i \) corresponds to the point \( (1, -1) \) in the complex plane) and a radius of 1. Thus, the correct answer is option (3), which states that the circle has a center at \( (-1, -1) \) and a radius of 1 unit.
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