Question:

Let R1 = {(a, b) ∈ N × N : |a – b| ≤ 13} and R2 = {(a, b) ∈ N × N : |a – b| ≠ 13}. Then on N:

Updated On: Sep 24, 2024
  • Both R1 and R2 are equivalence relations

  • Neither R1 nor R2 is an equivalence relation

  • R1 is an equivalence relation but R2 is not

  • R2 is an equivalence relation but R1 is not

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The Correct Option is B

Solution and Explanation

The correct answer is (B) : Neither R1 nor R2 is an equivalence relation
R1 = {(a, b) ∈ N × N : |a – b| ≤ 13} and
R2 = {(a, b) ∈ N × N : |a – b| ≠ 13}
In R1: ∵ |2 – 11| = 9 ≤ 13
∴ (2, 11) ∈ R1 and (11, 19) ∈ R1 but
(2, 19) ∉ R1
∴ R1 is not transitive
Hence R1 is not equivalence
In R: (13, 3) ∈ R2 and (3, 26) ∈ R2 but
(13, 26) ∉ R2 (∵ |13 – 26| = 13)
∴ R2 is not transitive
Hence R2 is not equivalence.

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Concepts Used:

Sets

In mathematics, a set is a well-defined collection of objects. Sets are named and demonstrated using capital letter. In the set theory, the elements that a set comprises can be any sort of thing: people, numbers, letters of the alphabet, shapes, variables, etc.

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Elements of a Set:

The items existing in a set are commonly known to be either elements or members of a set. The elements of a set are bounded in curly brackets separated by commas.

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Cardinal Number of a Set:

The cardinal number, cardinality, or order of a set indicates the total number of elements in the set.

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