Let R = {(1, 2), (2, 3), (3, 3)} be a relation defined on the set \( \{1, 2, 3, 4\} \). Then the minimum number of elements needed to be added in \( R \) so that \( R \) becomes an equivalence relation, is:}
To make the relation \( R = \{(1, 2), (2, 3), (3, 3)\} \) an equivalence relation on the set \( \{1, 2, 3, 4\} \), we need to ensure it satisfies three properties: reflexivity, symmetry, and transitivity.
1. Reflexivity: Each element must be related to itself. Therefore, we must add the pairs: \((1,1)\), \((2,2)\), \((4,4)\).
2. Symmetry: If \((a, b)\) is in the relation, then \((b, a)\) must also be in it. For existing pairs, add: \((2,1)\), \((3,2)\).
3. Transitivity: If \((a, b)\) and \((b, c)\) are in the relation, then \((a, c)\) must also be in it. Evaluate existing pairs:
Now, enumerating all added pairs, we find: \((1,1)\), \((2,2)\), \((4,4)\), \((2,1)\), \((3,2)\), \((1,3)\), \((3,1)\). Therefore, 7 elements are added in total.
Conclusion: The minimum number of elements to be added is \(7\).
How many possible words can be created from the letters R, A, N, D (with repetition)?
Let a line passing through the point $ (4,1,0) $ intersect the line $ L_1: \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} $ at the point $ A(\alpha, \beta, \gamma) $ and the line $ L_2: x - 6 = y = -z + 4 $ at the point $ B(a, b, c) $. Then $ \begin{vmatrix} 1 & 0 & 1 \\ \alpha & \beta & \gamma \\ a & b & c \end{vmatrix} \text{ is equal to} $
Resonance in X$_2$Y can be represented as
The enthalpy of formation of X$_2$Y is 80 kJ mol$^{-1}$, and the magnitude of resonance energy of X$_2$Y is: