Step 1: Simplifying \( S_1 \)
The compound statement \( S_1 \) is:
\[
S_1: (\neg p \vee q) \vee (\neg p \vee r)
\]
Using the associative and commutative properties of logical OR (\( \vee \)), we can simplify \( S_1 \):
\[
S_1 = \neg p \vee (q \vee r)
\]
Thus, \( S_1 \) simplifies to:
\[
S_1 = \neg p \vee (q \vee r)
\]
This means that \( S_1 \) is true if either \( p \) is false or at least one of \( q \) or \( r \) is true.
Step 2: Simplifying \( S_2 \)
The compound statement \( S_2 \) is:
\[
S_2: p \rightarrow (q \vee r)
\]
Recall that the implication \( p \rightarrow (q \vee r) \) is equivalent to:
\[
S_2 = \neg p \vee (q \vee r)
\]
Thus, \( S_2 \) is true if either \( p \) is false or at least one of \( q \) or \( r \) is true.
Step 3: Analyzing the truth values of \( S_1 \) and \( S_2 \)
- \( S_1 \) and \( S_2 \) are both equivalent in their form:
\[
S_1 = \neg p \vee (q \vee r)
\]
\[
S_2 = \neg p \vee (q \vee r)
\]
Therefore, \( S_1 \) and \( S_2 \) are logically equivalent, meaning they will have the same truth value.
Step 4: Evaluating the given statement
The question asks which of the following is NOT true: "If \( S_2 \) is false, then \( S_1 \) is true." Since \( S_1 \) and \( S_2 \) are logically equivalent, if \( S_2 \) is false, then \( S_1 \) will also be false. Therefore, the statement "If \( S_2 \) is false, then \( S_1 \) is true" is NOT true.
Step 5: Final Answer
The correct answer is:
If \( S_2 \) is false, then \( S_1 \) is true