Given: Parabola with equation: \[ x^2 = 8y \] Any point on this parabola can be represented as: \[ Q = (4t, 2t^2) \]
Let O = (0, 0) and point P divides the line segment OQ in the ratio 1:3 internally.
Using section formula:
Coordinates of P (h, k) are: \[ h = \frac{1 \cdot 4t + 3 \cdot 0}{1 + 3} = \frac{4t}{4} = t \] \[ k = \frac{1 \cdot 2t^2 + 3 \cdot 0}{1 + 3} = \frac{2t^2}{4} = \frac{t^2}{2} \] So, P = (t, t^2/2)
Now eliminate parameter t:
From \( h = t \), we get \( t = h \).
Substitute into k: \[ k = \frac{h^2}{2} \]
Hence, the locus of point P is: \[ y = \frac{x^2}{2} \Rightarrow x^2 = 2y \]
Final Answer: Option (D): \( x^2 = 2y \)
When a plane intersects a cone in multiple sections, several types of curves are obtained. These curves can be a circle, an ellipse, a parabola, and a hyperbola. When a plane cuts the cone other than the vertex then the following situations may occur:
Let ‘β’ is the angle made by the plane with the vertical axis of the cone
Read More: Conic Sections