To find the projection of \( \mathbf{c} - 2\hat{j} \) on \( \mathbf{a} \), first compute the vectors \( \mathbf{b} \) and \( \mathbf{c} \) using the given cross products. Then, use the projection formula: \[ \text{Proj}_{\mathbf{a}} \mathbf{v} = \frac{\mathbf{a} \cdot \mathbf{v}}{|\mathbf{a}|}. \] Substitute \( \mathbf{c} - 2\hat{j} \) and \( \mathbf{a} \) into the formula.
Final Answer: \( 2\sqrt{14} \).
For the reaction:
The correct order of set of reagents for the above conversion is :
Match List - I with List - II.