Let \( A = \{1,2,3,4,5,6,7,8\}, B = \{2,3,4,5,6,7,8,9\} \)
Total number of outcomes = \( 8 \times 8 = 64 \)
Now count the number of favorable pairs where \( a + b = 9 \):
From \( A \), possible values:
\[
(1,8), (2,7), (3,6), (4,5), (5,4), (6,3), (7,2)
\Rightarrow \text{Total = 7 favorable outcomes}
\]
\[
\text{Required Probability} = \frac{7}{64}
\]
Final Answer: (4) \(\frac{7}{64}\)