\(K_1>\frac{K_2}{3}\)
\(K_1< \frac{K_2}{3}\)
\(K_1=\frac{K_2}{3}\)
\(K_2=\frac{K_1}{3}\)
To solve this question, we need to apply the principles of the photoelectric effect as described by Albert Einstein in 1905. Let us understand the relationship between the wavelength of light and the maximum kinetic energy of photoelectrons emitted from a metallic surface:
For wavelength \(\lambda_1\):
\(K_1 = \frac{hc}{\lambda_1} - \phi = \frac{hc}{3\lambda_2} - \phi\)
For wavelength \(\lambda_2\):
\(K_2 = \frac{hc}{\lambda_2} - \phi\)
Thus, comparing the values, we get:
\(K_1 < \frac{K_2}{3}\)
Hence, the correct answer is: \(K_1 < \frac{K_2}{3}\).
The correct answer is (B) : \(K_1< \frac{K_2}{3}\)
\(K_1=\frac{hc}{λ_1}−\phi=\frac{hc}{3λ_2}−\phi….(i)\)
and
\(K_2=\frac{hc}{λ_2}−\phi….(ii)\)
from (i) and (ii) we can say
3K1 = K2 – 2φ
\(K_1<\frac{K_2}{3}\)
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
Which of the following best represents the temperature versus heat supplied graph for water, in the range of \(-20^\circ\text{C}\) to \(120^\circ\text{C}\)? 
When light shines on a metal, electrons can be ejected from the surface of the metal in a phenomenon known as the photoelectric effect. This process is also often referred to as photoemission, and the electrons that are ejected from the metal are called photoelectrons.
According to Einstein’s explanation of the photoelectric effect :
The energy of photon = energy needed to remove an electron + kinetic energy of the emitted electron
i.e. hν = W + E
Where,