Question

In an experiment with photoelectric effect, the stopping potential:

• A. increases with increase in the wavelength of the incident light
• B. increases with increase in the intensity of the incident light
• C. is \( \frac{1}{e} \) times the maximum kinetic energy of the emitted photoelectrons
• D. decreases with increase in the intensity of the incident light

Hint:

The stopping potential \( V_s \) is a key factor in the photoelectric effect, representing the potential needed to stop the emitted electrons. It is directly related to the maximum kinetic energy of the emitted photoelectrons.

Answer 1

The Correct Option is C

In the photoelectric effect, the energy of the emitted photoelectrons is given by: \[ E = h \nu - W \] where \( h \nu \) is the energy of the incident photons and \( W \) is the work function. The stopping potential \( V_s \) is related to the kinetic energy of the emitted photoelectrons, and it is given by: \[ eV_s = K_{\text{max}} \] where \( K_{\text{max}} \) is the maximum kinetic energy of the emitted photoelectrons. Hence, the stopping potential is \( \frac{1}{e} \) times the maximum kinetic energy of the emitted photoelectrons.