We are given that \( x \cdot \log x \cdot f'(x) + \log x \cdot f(x) \geq 1 \) for \( x \in [2, 4] \), and also that \( f(2) = \frac{1}{2} \) and \( f(4) = \frac{1}{4} \).
First, we differentiate the given inequality:
\[
\frac{d}{dx} \left( x \cdot \log x \cdot f(x) \right) \geq 0
\]
This leads to:
\[
\frac{d}{dx} \left( f(x) \cdot \log x \right) \geq 0
\]
Now, simplifying the derivatives:
\[
\frac{d}{dx} \left( (f(x) \cdot \log x) \right) \Rightarrow f'(x) \cdot \log x + f(x) \cdot \frac{1}{x} \geq 0
\]
This ensures that \( f(x) \) is increasing and positive in the interval \( [2, 4] \).
Next, we define a new function \( g(x) = \ln(x) f(x) - x \). We then find that \( g(x) \) is increasing in the interval \( [2, 4] \).
Now, we solve for the behavior of \( f(x) \) using the boundaries of the interval \( [2, 4] \):
\[
f(2) = \frac{1}{2}, \quad f(4) = \frac{1}{4}
\]
We compute the bounds and find that the value of \( f(x) \) falls between the values of \( \frac{1}{2} \) and \( \frac{1}{8} \), which leads to the conclusion that both statements (A) and (B) are true.