Step 1: Understanding the Parabola and Given Points
We are given the parabola $y^2 = 8x$. The equation of the parabola represents a standard parabola that opens to the right with the vertex at the origin $(0, 0)$.
The focus of the parabola, denoted by $F$, is at $(2, 0)$, since the general formula for a parabola of the form $y^2 = 4ax$ gives the focus at $(a, 0)$. Here, $a = 2$, so the focus is at $F(2, 0)$.
We are also given the point $P = (-2, 4)$ and two distinct points $Q$ and $Q'$ on the parabola such that the lines $PQ$ and $PQ'$ are tangents to the parabola at $Q$ and $Q'$. We need to determine which of the following statements is true:
Step 2: Statement (A) - The triangle $PFQ$ is a right-angled triangle
To determine if the triangle $PFQ$ is a right-angled triangle, we need to check if the angle $\angle PFQ$ is $90^\circ$. We know that the tangent at any point on the parabola makes an angle of $90^\circ$ with the line joining the point of tangency and the focus. Hence, since $PQ$ is tangent to the parabola at $Q$, and the focus is at $F$, the angle $\angle PFQ$ is indeed a right angle.
Therefore, statement (A) is TRUE.
Step 3: Statement (B) - The triangle $QPQ'$ is a right-angled triangle
For triangle $QPQ'$ to be right-angled, one of its angles must be $90^\circ$. The points $Q$ and $Q'$ are distinct points on the parabola, and the lines $PQ$ and $PQ'$ are tangents to the parabola at these points. Since the tangents at two distinct points on the parabola are perpendicular to the line joining those points with the focus, the angle between $PQ$ and $PQ'$ is $90^\circ$. This makes triangle $QPQ'$ a right-angled triangle.
Therefore, statement (B) is TRUE.
Step 4: Statement (D) - $F$ lies on the line joining $Q$ and $Q'$
This statement is related to a well-known property of parabolas: the two tangents drawn from any external point to a parabola always meet at the same angle at the focus. Since $Q$ and $Q'$ are points of tangency, the line joining them will pass through the focus $F$. This is because the tangents at $Q$ and $Q'$ must be symmetric with respect to the line joining $Q$ and $Q'$, and the focus lies on this line.
Therefore, statement (D) is TRUE.
Step 5: Conclusion
The correct statements are (A), (B), and (D). Thus, the answer is:
TRUE for all statements: (A), (B), (D).
Let one focus of the hyperbola \( H : \dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1 \) be at \( (\sqrt{10}, 0) \) and the corresponding directrix be \( x = \dfrac{9}{\sqrt{10}} \). If \( e \) and \( l \) respectively are the eccentricity and the length of the latus rectum of \( H \), then \( 9 \left(e^2 + l \right) \) is equal to:
If \( S \) and \( S' \) are the foci of the ellipse \[ \frac{x^2}{18} + \frac{y^2}{9} = 1 \] and \( P \) is a point on the ellipse, then \[ \min (SP \cdot S'P) + \max (SP \cdot S'P) \] is equal to:
Let $ a_0, a_1, ..., a_{23} $ be real numbers such that $$ \left(1 + \frac{2}{5}x \right)^{23} = \sum_{i=0}^{23} a_i x^i $$ for every real number $ x $. Let $ a_r $ be the largest among the numbers $ a_j $ for $ 0 \leq j \leq 23 $. Then the value of $ r $ is ________.
Let $ \mathbb{R} $ denote the set of all real numbers. Then the area of the region $$ \left\{ (x, y) \in \mathbb{R} \times \mathbb{R} : x > 0, y > \frac{1}{x},\ 5x - 4y - 1 > 0,\ 4x + 4y - 17 < 0 \right\} $$ is
The center of a disk of radius $ r $ and mass $ m $ is attached to a spring of spring constant $ k $, inside a ring of radius $ R>r $ as shown in the figure. The other end of the spring is attached on the periphery of the ring. Both the ring and the disk are in the same vertical plane. The disk can only roll along the inside periphery of the ring, without slipping. The spring can only be stretched or compressed along the periphery of the ring, following Hooke’s law. In equilibrium, the disk is at the bottom of the ring. Assuming small displacement of the disc, the time period of oscillation of center of mass of the disk is written as $ T = \frac{2\pi}{\omega} $. The correct expression for $ \omega $ is ( $ g $ is the acceleration due to gravity): 