Consider a sequence of independent Bernoulli trials with probability of success in each trial being $\dfrac{1}{5}$. Then which of the following statements is/are TRUE?
Step 1: Define the model.
Let $p = \dfrac{1}{5}$ be the probability of success.
We use properties of geometric and negative binomial distributions.
Step 2: Expected number of trials for the first success.
For a geometric distribution,
\[
E(X) = \frac{1}{p} = 5.
\]
Hence, (A) is true.
Step 3: Expected number of successes in 50 trials.
For a binomial distribution $B(n=50, p=\frac{1}{5})$,
\[
E(X) = np = 50 \times \frac{1}{5} = 10.
\]
Hence, (B) is true.
Step 4: Expected number of failures before the first success.
For a geometric distribution, the expected number of failures is
\[
E(X - 1) = \frac{1 - p}{p} = 4.
\]
Hence, (C) is true.
Step 5: Expected number of trials for the second success.
For the negative binomial distribution (r = 2, p = 1/5):
\[
E(X) = \frac{r}{p} = \frac{2}{1/5} = 10.
\]
Hence, (D) is also true.
Step 6: Conclusion.
\[
\boxed{\text{All statements (A), (B), (C), and (D) are true.}}
\]
Let $X$ and $Y$ be independent random variables with respective moment generating functions $M_X(t) = \dfrac{(8 + e^t)^2}{81}$ and $M_Y(t) = \dfrac{(1 + 3e^t)^3}{64}$, $-\infty < t < \infty$. Then $P(X + Y = 1)$ equals .............. (round off to two decimal places).
Consider a sequence of independent Bernoulli trials with probability of success in each trial being $\dfrac{1}{3}$. Let $X$ denote the number of trials required to get the second success. Then $P(X \ge 5)$ equals