Given data:
\[ |A| = 2, \quad \text{trace}(A) = -3 \]
Matrix Equation:
We are given: \[ A^2 + xA + yI = 0, \]
where \(I\) is the identity matrix.
Interpreting the Condition:
Since the given condition relates points \((x, y)\) that lie on a hyperbola whose transverse axis is parallel to the \(x\)-axis, we need to find the eccentricity \(e\) and the length of the latus rectum \(\ell\).
Given Information:
The problem states that \(|A| = 2\) and \(\text{trace}(A) = -3\).
Using these conditions, we can establish that: \[ A = \begin{bmatrix} a & b \\ c & d \end{bmatrix}, \]
where \(a + d = -3\) and \(ad - bc = 2\).
Additional Conditions:
Since the given problem does not provide sufficient information about the hyperbola’s parameters (such as the specific form of the matrix \(A\) or further constraints on \(x\) and \(y\)), determining the exact values of the eccentricity \(e\) and the latus rectum length \(\ell\) is not feasible.
Conclusion:
Based on the given conditions, the problem states an answer of \(e^4 + \ell^4 = 25\) as per the NTA’s answer key, but the derivation is incomplete due to insufficient data.
Match List-I with List-II
List-I (Matrix) | List-II (Inverse of the Matrix) |
---|---|
(A) \(\begin{bmatrix} 1 & 7 \\ 4 & -2 \end{bmatrix}\) | (I) \(\begin{bmatrix} \tfrac{2}{15} & \tfrac{1}{10} \\[6pt] -\tfrac{1}{15} & \tfrac{1}{5} \end{bmatrix}\) |
(B) \(\begin{bmatrix} 6 & -3 \\ 2 & 4 \end{bmatrix}\) | (II) \(\begin{bmatrix} \tfrac{1}{5} & -\tfrac{2}{15} \\[6pt] -\tfrac{1}{10} & \tfrac{7}{30} \end{bmatrix}\) |
(C) \(\begin{bmatrix} 5 & 2 \\ -5 & 4 \end{bmatrix}\) | (III) \(\begin{bmatrix} \tfrac{1}{15} & \tfrac{7}{30} \\[6pt] \tfrac{2}{15} & -\tfrac{1}{30} \end{bmatrix}\) |
(D) \(\begin{bmatrix} 7 & 4 \\ 3 & 6 \end{bmatrix}\) | (IV) \(\begin{bmatrix} \tfrac{2}{15} & -\tfrac{1}{15} \\[6pt] \tfrac{1}{6} & \tfrac{1}{6} \end{bmatrix}\) |
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)