Let $A B C$ be the triangle with $A B=1, A C=3$ and $\angle B A C=\frac{\pi}{2}$ If a circle of radius $r>0$ touches the sides $A B, A C$ and also touches internally the circumcircle of the triangle $A B C$, then the value of $r$ ___
Correct Answer: 0.84
Solution and Explanation
Let's suppose that A be (0, 0), B(1, 0) and C(0, 3).
Hence, AB and AC lies on x-axis and y-axis respectively.
Therefore, the equation of circle touching both x-axis and y-axis is as follows :
(x - h)2 + (y - h)2 = h2 (∵ h = k = r)
So, it touches the cirlce as :
\((x-\frac{1}{2})^2+(y-\frac{3}{2})^2=\frac{5}{2}\)
Therefore, c1c2 = |r1 - r2|
Now,
\(\sqrt{(h-\frac{1}{2})^2+(h-\frac{3}{2})^2}=|h-\frac{\sqrt5}{\sqrt2}|\)
\(⇒h^2+\frac{1}{4}-h+h^2+\frac{9}{4}-3h\)
\(=h^2+\frac{5}{2}-\sqrt{10}h\)
\(⇒h^2+(\sqrt{10}-4)h=0\)
\(⇒h=4-\sqrt10\)
Hence, \(r=4-\sqrt{10}=0.84\)
∴ the correct answer is 0.84
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Concepts Used:
Circle
A circle can be geometrically defined as a combination of all the points which lie at an equal distance from a fixed point called the centre. The concepts of the circle are very important in building a strong foundation in units likes mensuration and coordinate geometry. We use circle formulas in order to calculate the area, diameter, and circumference of a circle. The length between any point on the circle and its centre is its radius.
Any line that passes through the centre of the circle and connects two points of the circle is the diameter of the circle. The radius is half the length of the diameter of the circle. The area of the circle describes the amount of space that is covered by the circle and the circumference is the length of the boundary of the circle.
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