Explanation of Lassaigne’s Test: - Lassaigne’s test involves the conversion of elements such as nitrogen, sulphur, phosphorus, and halogens present in an organic compound into their ionic forms by fusion with sodium metal. - The resulting sodium fusion extract (also known as Lassaigne’s extract) can be tested for these elements using specific reagents.
- Detection of Nitrogen: The sodium fusion extract is treated with ferrous sulphate (FeSO$_4$) and acidified with sulphuric acid. The formation of a Prussian blue colour indicates the presence of nitrogen.
Detection of Sulphur: The extract is treated with lead acetate solution. A black precipitate of lead sulphide (PbS) indicates the presence of sulphur.
Detection of Halogens: The extract is treated with silver nitrate (AgNO$_3$) solution after acidification with nitric acid. The formation of a white, yellow, or pale yellow precipitate indicates the presence of chlorine, bromine, or iodine, respectively.
- Detection of Phosphorous: Phosphorous is detected by the formation of a yellow precipitate of ammonium phosphomolybdate when the extract is treated with ammonium molybdate in the presence of nitric acid.
Conclusion: Lassaigne’s test is used for the detection of nitrogen, sulphur, phosphorus, and halogens.
Among the following cations, the number of cations which will give characteristic precipitate in their identification tests with
\(K_4\)[Fe(CN)\(_6\)] is : \[ {Cu}^{2+}, \, {Fe}^{3+}, \, {Ba}^{2+}, \, {Ca}^{2+}, \, {NH}_4^+, \, {Mg}^{2+}, \, {Zn}^{2+} \]
Find the equivalent capacitance between A and B, where \( C = 16 \, \mu F \).
If the equation of the parabola with vertex \( \left( \frac{3}{2}, 3 \right) \) and the directrix \( x + 2y = 0 \) is \[ ax^2 + b y^2 - cxy - 30x - 60y + 225 = 0, \text{ then } \alpha + \beta + \gamma \text{ is equal to:} \]