Integrated rate law equation for a first order gas phase reaction is given by (where $P_i$ is initial pressure and $P_t$ is total pressure at time t)

Question

Integrated rate law equation for a first order gas phase reaction is given by (where $P_i$ ​ is initial pressure and  $P_t$ ​ is total pressure at time t)

cdquestions Admin · Accepted Answer

Consider the reaction: $$ A \rightarrow B + C $$ Initial pressures: $$ P_i \quad 0 \quad 0 $$ After reaction: $$ P_i - x \quad x \quad x $$ Total pressure at time $t$: $$ P_t = P_i + x $$ Therefore: $$ P_i - x = P_i - P_t + P_i $$ $$ = 2P_i - P_t $$ Hence, $$ k = \frac{2.303}{t}\times \log \frac{P_i}{2P_i - P_t} $$

Answer

$ k = \frac{2.303}{t} \times \log \frac{P_i}{(2P_i - P_t)} $

Answer

$ k = \frac{2.303}{t} \times \log \frac{2P_i}{(2P_i - P_t)} $

Answer

$ k = \frac{2.303}{t} \times \log \frac{(2P_i - P_t)}{P_i} $

Answer

$ k = \frac{2.303}{t} \times \log \frac{P_i}{(2P_i - P_t)} $

Initial concentration of [𝐴] 𝑚𝑜𝑙 $𝐿 ^{−1}$	Initial concentration of [𝐵] 𝑚𝑜𝑙$𝐿 ^{−1}$	Initial rate of formation of [𝐶] 𝑚𝑜𝑙 $𝐿^{−1} 𝑠 ^{−1}$
0.2	0.2	0.3
0.4	0.2	0.6
0.4	0.4	2.4

Integrated rate law equation for a first order gas phase reaction is given by (where \(P_i\) is initial pressure and \(P_t\) is total pressure at time t)

The Correct Option is A

Solution and Explanation

Top Questions on Chemical Kinetics

Questions Asked in JEE Main exam

Integrated rate law equation for a first order gas phase reaction is given by (where \(P_i\)​ is initial pressure and \(P_t\)​ is total pressure at time t)

The Correct Option is A

Solution and Explanation

Top Questions on Chemical Kinetics

Questions Asked in JEE Main exam

Integrated rate law equation for a first order gas phase reaction is given by (where \(P_i\) is initial pressure and \(P_t\) is total pressure at time t)