Question

In which of the following reactions, major product is matched correctly?

• A.
• B.
• C.
• D.

Hint:

In nucleophilic substitution reactions, identify the nucleophile and electrophile correctly. The nucleophile will replace the leaving group (halide ion) in the process. Ensure the correct product is identified based on the reagents used.

Answer 1

The Correct Option is C

In this question, we are considering nucleophilic substitution reactions.
Let's analyze each option to determine which correctly matches the major product.

1. Option 1: \( O\text{Na}^+ + \text{EtBr} \longrightarrow \text{OMe} \) This reaction is incorrect because the nucleophile \( O\text{Na}^+ \) does not react with \( \text{EtBr} \) to form \( \text{OMe} \).
The product should be \( \text{OEt} \), not \( \text{OMe} \), which is inconsistent with the reaction conditions.

2. Option 2: \( \text{t-ButO}^-\text{Na}^+ + \text{EtBr} \longrightarrow \text{t-ButO}-\text{Et} \) This reaction is incorrect because the nucleophile \( \text{t-ButO}^- \) (tert-butoxide) reacts with \( \text{EtBr} \) to form \( \text{t-ButO}-\text{Et} \), which is correct in terms of nucleophilic substitution, but not the major product expected for this type of reaction.

3. Option 3: \( O\text{Na}^+ + \text{nPrBr} \longrightarrow \text{O-nPr} \) This is the correct answer.
Here, the nucleophile \( O\text{Na}^+ \) reacts with \( \text{nPrBr} \) (n-propyl bromide) in a nucleophilic substitution, displacing the bromide ion and forming the product \( \text{O-nPr} \), which is the expected major product.

4. Option 4: \( \text{Sec ButO}K^+ + \text{EtBr} \longrightarrow \text{Sec But} - \text{OEt} \)
This is incorrect.

The expected product is \( \text{Sec ButO}-\text{Et} \), but the formation of this product is unlikely given the reagents and expected reaction type. Thus, the correct match is Option 3.