In the wet tests for identification of various cations by precipitation, which transition element cation doesn’t belong to group IV in qualitative inorganic analysis?
\(Fe^{3+}\)
\(Zn^{2+}\)
\(Co^{2+}\)
\(Ni^{2+}\)
Step 1: Understanding the Grouping of Cations in Qualitative Analysis
In qualitative inorganic analysis, cations are classified into groups based on their precipitation behavior with specific reagents. The classification is as follows:
Group III: Includes \(\text{Fe}^{3+}\), \(\text{Al}^{3+}\), and \(\text{Cr}^{3+}\), which precipitate as hydroxides in the presence of \(\text{NH}_4\text{OH}\) and \(\text{NH}_4\text{Cl}\).
Group IV: Includes \(\text{Zn}^{2+}\), \(\text{Co}^{2+}\), and \(\text{Ni}^{2+}\), which precipitate as sulfides in the presence of \(\text{H}_2\text{S}\) in neutral or slightly acidic medium.
Step 2: Analysis of the Cations
\(\text{Fe}^{3+}\): Belongs to Group III, as it forms \(\text{Fe(OH)}_3\) precipitate with \(\text{NH}_4\text{OH}\).
\(\text{Zn}^{2+}\), \(\text{Co}^{2+}\), \(\text{Ni}^{2+}\): Belong to Group IV, as they precipitate as sulfides (\(\text{ZnS}\), \(\text{CoS}\), \(\text{NiS}\)) with \(\text{H}_2\text{S}\).
Conclusion: \(\text{Fe}^{3+}\) does not belong to Group IV. Therefore, the correct answer is (1) \(\text{Fe}^{3+}\).
Match List I with List II:
Choose the correct answer from the options given below:
Match List I with List II:
Choose the correct answer from the options given below:
Which of the following statements are true?
A. Unlike Ga that has a very high melting point, Cs has a very low melting point.
B. On Pauling scale, the electronegativity values of N and C are not the same.
C. $Ar, K^{+}, Cl^{–}, Ca^{2+} and S^{2–}$ are all isoelectronic species.
D. The correct order of the first ionization enthalpies of Na, Mg, Al, and Si is Si $>$ Al $>$ Mg $>$ Na.
E. The atomic radius of Cs is greater than that of Li and Rb.
Choose the correct answer from the options given below:
A square loop of sides \( a = 1 \, {m} \) is held normally in front of a point charge \( q = 1 \, {C} \). The flux of the electric field through the shaded region is \( \frac{5}{p} \times \frac{1}{\varepsilon_0} \, {Nm}^2/{C} \), where the value of \( p \) is: