Solution:
In this problem, we need to evaluate the stability and properties of different oxidation states of aluminum ($Al$) and thallium ($Tl$). Let's analyze each statement:
- (A) $Tl^{3+}$ is a powerful oxidizing agent: This is true. Thallium in the +3 oxidation state is known to be a strong oxidizing agent because it can readily gain electrons to get reduced to $Tl^+$, which is more stable.
- (B) $Al^{3+}$ does not get reduced easily: This is true. Aluminum in the +3 state forms a very stable ion and does not easily gain electrons to get reduced.
- (C) Both $Al^{3+}$ and $Tl^{3+}$ are very stable in solution: This statement is incorrect. Thallium($Tl$) in the +3 state is not very stable and tends to get reduced to the more stable +1 state ($Tl^+$).
- (D) $Tl^+$ is more stable than $Tl^{3+}$: This is true. The +1 oxidation state is more stable for thallium due to the inert pair effect.
- (E) $Al^{3+}$ and $Tl^+$ are highly stable: This is true. Aluminum in the +3 state and Thallium in the +1 state are both stable in solution.
Conclusion:
Upon analyzing the statements, the correct ones are (A), (B), (D), and (E). Therefore, the correct answer is:
(A), (B), (D) and (E) only