Consider the following reactions $ A + HCl + H_2SO_4 \rightarrow CrO_2Cl_2$ + Side Products Little amount $ CrO_2Cl_2(vapour) + NaOH \rightarrow B + NaCl + H_2O $ $ B + H^+ \rightarrow C + H_2O $ The number of terminal 'O' present in the compound 'C' is ______
Consider the following reactions $ A + HCl + H_2SO_4 \rightarrow CrO_2Cl_2$ + Side Products Little amount $ CrO_2Cl_2(vapour) + NaOH \rightarrow B + NaCl + H_2O $ $ B + H^+ \rightarrow C + H_2O $ The number of terminal 'O' present in the compound 'C' is ______
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Correct Answer: 6
Solution and Explanation
\( Cr_2O_7^{2-} + HCl + H_2SO_4 \rightarrow CrO_2Cl_2 \)
\( CrO_2Cl_2(vapour) + NaOH \rightarrow Na_2CrO_4 + NaCl + H_2O \)
\( Na_2CrO_4 + H^+ \rightarrow Na_2Cr_2O_7 + H_2O \)
\( 2Na_2CrO_4 + 2H^+ \rightarrow Na_2Cr_2O_7 + 2Na^+ + H_2O \)
\( CrO_4^{2-} \xrightarrow{H^+} Cr_2O_7^{2-} \)
No of terminal "O" = 6
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