Question

In the reaction: \(\text{Aniline} \xrightarrow{\text{NaNO}_2/\text{dil. HCl}} P \xrightarrow{\text{Phenol/NaOH}} Q\)

• A. $C_6​H_5​N_2​Cl$
• B. Ortho-hydroxyazobenzene
• C. Para-hydroxyazobenzene
• D. Meta-hydroxyazobenzene

Hint:

Aniline diazotizes to benzene diazonium chloride (P), which reacts with phenol to form para-hydroxyazobenzene (Q).

Answer 1

The Correct Option is C

Aniline is first diazotized using sodium nitrite (NaNO2​) and dilute HCl to form benzene diazonium chloride (P). This intermediate reacts with phenol under basic conditions to produce para-hydroxyazobenzene (Q) as the major product due to preferential para-position substitution in phenol.