Question:

In the given volume (V) - absolute temperature (T) graph of an ideal gas, the relation between the pressures $ P_1 $ and $ P_2 $ is

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In ideal gas law problems, remember that pressure and temperature are directly proportional at constant volume.
Updated On: May 9, 2025
  • \( P_1 = \frac{P_2}{2} \)
  • \( P_1 = \frac{P_2}{3} \)
  • \( P_1 = 3 P_2 \)
  • \( P_1 = 2 P_2 \)
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The Correct Option is A

Solution and Explanation

In the volume-temperature graph for an ideal gas, the relation between the pressure and temperature for an ideal gas is given by the equation of state: \[ P \propto T \] Since the graph shows two different pressures at different temperatures, the relation between \( P_1 \) and \( P_2 \) is found to be: \[ P_1 = \frac{P_2}{2} \]
Thus, the correct relation is \( P_1 = \frac{P_2}{2} \).
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