In the given circuit, the current \(I_x\) (in mA) is \(\_\_\_\_\).
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Solution and Explanation
The circuit consists of a 5 mA current source, a dependent current source \(1000 I_0\), and resistors. Use Kirchhoff's Current Law (KCL) to analyze the node with \(I_x\). Step 2: Define the known currents.
Given \(I_0 = 2 \, {mA}\), the dependent source generates a current of: \[ 1000 I_0 = 1000 \times 2 \, {mA} = 2 \, {A}. \] Step 3: Determine \(I_x\).
The current \(I_x\) flows through the 1 k\(\Omega\) resistor. Based on current division and balancing the node currents, we find: \[ I_x = 2 \, {mA}. \] Final Answer: \[\boxed{{2}}\]
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- The relationship between any \(N\)-length sequence \(x[n]\) and its corresponding \(N\)-point discrete Fourier transform \(X[k]\) is defined as: \[ X[k] = \mathcal{F}\{x[n]\}. \] Another sequence \(y[n]\) is formed as: \[ y[n] = \mathcal{F}\{\mathcal{F}\{\mathcal{F}\{x[n]\}\}\}. \] For the sequence \(x[n] = \{1, 2, 1, 3\}\), the value of \(y[0]\) is \(\_\_\_\_\).
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\includegraphics[width=0.5\linewidth]{17.png}- GATE EC - 2025
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