Question:

In the cube of side $'a'$ shown in the figure, the vector from the central point of the face $ABOD$ to the central point of the face $BEFO$ will be:

Updated On: Sep 27, 2024
  • $\frac{1}{2} a \left(\hat{i} -\hat{k}\right) $
  • $\frac{1}{2} a \left(\hat{j} -\hat{i}\right) $
  • $\frac{1}{2} a \left(\hat{k} -\hat{i}\right) $
  • $\frac{1}{2} a \left(\hat{j} -\hat{k}\right) $
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The Correct Option is B

Solution and Explanation

$\vec{r}_{g} = \frac{a}{2} \hat{i} + \frac{a}{2} \hat{k} $
$ \vec{r}_{H} =\frac{a}{2} \hat{j} + \frac{a}{2} \hat{k} $
$\vec{ r}_{H} - \vec{r}_{g} = \frac{a}{2} \left(\hat{j} - \hat{i}\right) $
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration