\( 40 \, \text{m} \)
\(20 \, \text{m} \)
We are given the following data:
The equation is: \[ v^2 = u^2 - 2gh \] where \( v \) is the final velocity at the highest point, which is 0 m/s.
\[ 0^2 = (20)^2 - 2 \times 10 \times h \] \[ 0 = 400 - 20h \] \[ 20h = 400 \] \[ h = \frac{400}{20} = 20 \, \text{m} \]
The ball will rise to a maximum height of \( 20 \, \text{m} \).
Option 2: 20 m