Comprehension
In the circuit shown below, the switch $S$ is connected to position $P$ for a long time so that the charge on the capacitor becomes $q _{1}\, \mu C$. Then $S$ is switched to position $Q$. After a long time, the charge on the capacitor is $q _{2}\, \mu C$
Question: 1
The magnitude of q1 is _____.
The magnitude of q1 is _____.
Updated On: Mar 20, 2024
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Correct Answer: 1.33
Solution and Explanation
With switch S at position P after long time potential difference across capacitor branch
\(\frac{4 \times 1}{3}=\frac{4}{3}\) v
Charge on capacitor q1μC = (\(\frac{4}{3}\)) μC
\(⇒\)q1 = \(\frac{4}{3}\) = 1.33
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Question: 2
The magnitude of q2 is_____.
The magnitude of q2 is_____.
Updated On: Mar 20, 2024
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Correct Answer: 0.67
Solution and Explanation
With switch S at position Q after long time potential difference across the capacitor
= potential difference across a resistance of 1 ohm.
Charge on capacitor q2μC = (\(\frac{2}{3}\)) μC
\(⇒ q_2 = 0.67\)
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