Question:

In the Argand plane, the values of \( z \) satisfying the equation \( |z - 1| = |i(z + 1)| \) lie on:

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When solving modulus equations involving complex numbers, convert \( z = x + iy \) and compare magnitudes to derive geometric loci.
Updated On: May 13, 2025
  • the Y-axis
  • a Parabola
  • a Hyperbola
  • the X-axis
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The Correct Option is A

Solution and Explanation

Let \( z = x + iy \). Then, \[ |z - 1| = \sqrt{(x - 1)^2 + y^2}, \quad |i(z + 1)| = |i(x + 1 + iy)| = \sqrt{(x + 1)^2 + y^2} \] Equating: \[ (x - 1)^2 + y^2 = (x + 1)^2 + y^2 \Rightarrow x^2 - 2x + 1 = x^2 + 2x + 1 \Rightarrow -2x = 2x \Rightarrow x = 0 \] So, the locus is \( x = 0 \), i.e., the Y-axis.
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