In bromination of Propyne, with Bromine 1,1,2,2-tetrabromopropane is obtained in 27% yield. The amount of 1,1,2,2-tetrabromopropane obtained from 1 g of Bromine in this reaction is _______ × 10–1 g. (Nearest integer)
(Molar Mass : Bromine = 80 g/mol)
(Molar Mass : Bromine = 80 g/mol)
Correct Answer: 3
Solution and Explanation
2 moles Br2=1 mole 1,1,2,2-tetrabromopropane
\(\frac{1}{160} \, \text{mole Br}_2 = \frac{1}{2} \times \frac{1}{160} \, \text{mole 1,1,2,2-tetrabromopropane}\)
But yield of reaction is only 27%
Moles of 1,1,2,2-tetrabromopropane \(=\)\(\frac{1}{2} \times \frac{1}{160} \times \frac{27}{100}\)
Molar mass of 1,1,2,2-tetrabromopropane = 360 g
Mass of 1,1,2,2-tetrabromopropane\(=\)\(12 \times \frac{1}{160} \times \frac{27}{100} \times 360 \, \text{g}\)
\(= 3 × 10^{–1} \text{g}\)
So, the answer is 3.
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Hydrocarbons
Hydrocarbons can be described as organic compounds that consists only hydrogen and carbon atoms. These compounds are of different types and thereby have distinct natures. Hydrocarbons are colorless gases and are known for discharging faint odours. These have been categorized under four major classes named as alkynes, alkanes, alkenes, and aromatic hydrocarbons.
Types of Hydrocarbons
- Saturated hydrocarbons - Saturated hydrocarbons are those compounds where there is a single bond exists between carbon atoms and are saturated with atoms of hydrogen.
- Unsaturated hydrocarbons - Hydrocarbons comprises of at least one double or triple bond between carbon atoms are known as unsaturated hydrocarbons.
- Aliphatic hydrocarbons - The term denotes the hydrocarbons formed as an outcome of the chemical degradation of fats. Aliphatic hydrocarbons are basically chemical compounds.
- Aromatic hydrocarbons - They are distinguished because of the presence of benzene rings in them. They give away distinct types of aroma. These hydrocarbons comprises of only hydrogen and carbon atoms.