Question:

How many moles of oxygen are required to completely combust 1 mole of propane (C\(_3\)H\(_8\))?

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Tip: Always balance the combustion of hydrocarbons carefully — follow the pattern C → CO\(_2\), H → H\(_2\)O, then balance O\(_2\).
Updated On: May 30, 2025
  • 4 moles
  • 6 moles
  • 5 moles
  • 3 moles
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The Correct Option is C

Approach Solution - 1

To determine the moles of oxygen required for the complete combustion of 1 mole of propane (C\(_3\)H\(_8\)), we must first write the balanced chemical equation for the combustion process. The combustion of propane is represented by:

C\(_3\)H\(_8\) + 5O\(_2\) → 3CO\(_2\) + 4H\(_2\)O

This equation indicates that 1 mole of propane (C\(_3\)H\(_8\)) reacts with 5 moles of oxygen (O\(_2\)) to produce 3 moles of carbon dioxide (CO\(_2\)) and 4 moles of water (H\(_2\)O).

Therefore, 5 moles of oxygen are required to completely combust 1 mole of propane.

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Approach Solution -2

To determine how many moles of oxygen are required to completely combust 1 mole of propane (C3H8), we first need to write the balanced chemical equation for the combustion reaction:
C3H8 + O2 → CO2 + H2O
Let's balance this equation step by step:
  1. Start with the carbon atoms. We have 3 carbons in propane, so we need 3 CO2:
    C3H8 + O2 → 3CO2 + H2O
  2. Next, balance the hydrogen atoms. There are 8 hydrogens in propane, requiring 4 H2O:
    C3H8 + O2 → 3CO2 + 4H2O
  3. Finally, balance the oxygen atoms. We have 3 CO2 contributing 6 oxygen atoms and 4 H2O contributing 4 oxygen atoms, for a total of 10 oxygen atoms required from O2. Since each O2 molecule provides 2 oxygen atoms, 5 O2 molecules are needed:
    C3H8 + 5O2 → 3CO2 + 4H2O
Therefore, 5 moles of oxygen (O2) are required to completely combust 1 mole of propane (C3H8).
SubstanceMoles in Reaction
C3H81
O25
CO23
H2O4
Thus, the correct answer is 5 moles.
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