In a Young’s double slit experiment, two slits are illuminated with light of wavelength \(800 \, \text{nm}\). The first minimum is detected at \(P\). The value of slit separation \(a\) is:
For Young’s double-slit experiments:
• Use the condition for minima or maxima to relate wavelength, slit separation, and screen distance.
• Ensure units are consistent when calculating.
Condition for Minima: Path difference for the first minimum:
\[ \Delta x = \frac{\lambda}{2}. \]
Slit Separation: From geometry:
\[ a = \frac{\lambda D}{\Delta x}. \]
Substituting values:
\[ a = \frac{800 \times 10^{-9} \times 5 \times 10^{-2}}{0.5 \times 10^{-3}} = 0.2 \, \text{mm}. \]
Final Answer: 0.2 mm

In the first configuration (1) as shown in the figure, four identical charges \( q_0 \) are kept at the corners A, B, C and D of square of side length \( a \). In the second configuration (2), the same charges are shifted to mid points C, E, H, and F of the square. If \( K = \frac{1}{4\pi \epsilon_0} \), the difference between the potential energies of configuration (2) and (1) is given by: